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[libgcc] Provide symbol to handle gcc's implicit calls to memset()
On some architectures (such as ARM), gcc will insert implicit calls to memset(). Handle these using the same mechanism as for the implicit calls to memcpy() used by x86. Signed-off-by: Michael Brown <mcb30@ipxe.org>
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/** @file | ||
* | ||
* gcc sometimes likes to insert implicit calls to memcpy() and | ||
* memset(). Unfortunately, there doesn't seem to be any way to | ||
* prevent it from doing this, or to force it to use the optimised | ||
* versions as seen by C code; it insists on inserting symbol | ||
* references to "memcpy" and "memset". We therefore include wrapper | ||
* functions just to keep gcc happy. | ||
* | ||
*/ | ||
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#include <string.h> | ||
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void * gcc_implicit_memcpy ( void *dest, const void *src, | ||
size_t len ) asm ( "memcpy" ); | ||
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void * gcc_implicit_memcpy ( void *dest, const void *src, size_t len ) { | ||
return memcpy ( dest, src, len ); | ||
} | ||
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void * gcc_implicit_memset ( void *dest, int character, | ||
size_t len ) asm ( "memset" ); | ||
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void * gcc_implicit_memset ( void *dest, int character, size_t len ) { | ||
return memset ( dest, character, len ); | ||
} |
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